Mathematical christmas

Multiply by m on both sides then expand the brackets: m*e^((r^2)y)=m*(x/m-sa) => me^rry=xm/m-sam => me^rry=x-mas

The purpose of multiplying m was to get rid of the fraction and cancel it’s term so it shouldn’t exist on the right side of this equation anymore why is it still there I am confusion

m*((x/m)-sa) simplifies to m*(x/m)-m*sa. The m is multiplied over both terms on the right hand side of the equation because it is subtracting (sa).

But with that logic it would be auto-cancelled as you’re multiplying everything on the right by your denominator removing M entirely...?

The right hand side consists of two terms: a fraction (x/m) and another term (sa) which is subtracted from the first term. Notice the second term is not part of the fraction and is not divided by m. Now when we multiply this group of terms ((x/m)-(sa)) by m, we multiply each of the terms individually, to give (mx/m)-(sam), so I don't understand your logic.

You’d keep all terms in one bracket to multiply so: m[(x/m)-sa]
Therefore with your division and multiplication it would cancel ridding you of your m term.
Am I missing something here or am I just retarded

What happens to the term sa when you expand the brackets? Does it have another m to cancel it out?

No?

Oh my God you have to distribute oh my Godddddd
I’m actually retarded

Yayy you figured it out! But don't call yourself retarded. Mistakes like this happens to the best of us.